<html><head><meta name="color-scheme" content="light dark"></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">\documentclass[12pt] {article} \usepackage[T1]{fontenc} 
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\renewcommand{\thesubsection}{\textcolor{blue}{Exercice \Roman{subsection}}} 
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\begin{document}


\begin{center}\section*{\textcolor{red}{Exercices d'Ã©tudes de variations}}\end{center}


Ã‰tudier les variations des fonctions suivantes :

\begin{enumerate}[1)]
\item $f(x)=-x^3+3x$

\bigskip

\item $f(x)=x^3-x^2-x+1$

\bigskip

\item $f(x)=x^4-8x^2+8$

\bigskip

\item $f(x)=\dfrac{-4x}{x^2+1}$

\bigskip

\item $f(x)=\dfrac{x^2-x-2}{(x-1)^2}$ $(x\neq 1)$

\bigskip

\item $f(x)=x-1+\dfrac{4}{x-2}$ ($x\neq 2$)
\end{enumerate}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\vspace{1cm}
\begin{center}\section*{\textcolor{red}{Exercices d'Ã©tudes de variations}}\end{center}


Ã‰tudier les variations des fonctions suivantes :

\begin{enumerate}[1)]
\item $f(x)=-x^3+3x$

\bigskip

\item $f(x)=x^3-x^2-x+1$

\bigskip

\item $f(x)=x^4-8x^2+8$

\bigskip

\item $f(x)=\dfrac{-4x}{x^2+1}$

\bigskip

\item $f(x)=\dfrac{x^2-x-2}{(x-1)^2}$ $(x\neq 1)$

\bigskip

\item $f(x)=x-1+\dfrac{4}{x-2}$ ($x\neq 2$)
\end{enumerate}


%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\vspace{1cm}
\begin{center}\section*{\textcolor{red}{Exercices d'Ã©tudes de variations}}\end{center}


Ã‰tudier les variations des fonctions suivantes :

\begin{enumerate}[1)]
\item $f(x)=-x^3+3x$

\bigskip

\item $f(x)=x^3-x^2-x+1$

\bigskip

\item $f(x)=x^4-8x^2+8$

\bigskip

\item $f(x)=\dfrac{-4x}{x^2+1}$

\bigskip

\item $f(x)=\dfrac{x^2-x-2}{(x-1)^2}$ $(x\neq 1)$

\bigskip

\item $f(x)=x-1+\dfrac{4}{x-2}$ ($x\neq 2$)
\end{enumerate}

\label{fin}
\end{document}  </pre></body></html>